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# differences in lat/long fs2004

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I slew to a position of N33* 56.33', W118* 24.29' at KJFK

This converted to decimal is 33.9425, -118.4081

If this value is read via FSUIPC within FSinterrogate I get the decimal value of 33.93883, -118.40483. Converting this back to DHM gives value of N33* 56.24', W118* 24.17'.

Why is the value read back via FSUIPC different to the value that FS2004 thinks I am currently in?

thanks

Gray

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I slew to a position of N33* 56.33', W118* 24.29' at KJFK

This converted to decimal is 33.9425, -118.4081

No it isn't. It's 33.938833 and 118.404833.

I think you are mixing up minutes (56.33') with minutes and seconds (56' 33").

Why is the value read back via FSUIPC different to the value that FS2004 thinks I am currently in?

It isn't, it is identical. They come from the same place in FS. You need to understand the units.

Regards

Pete

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Thanks

so FS2004 format is Deg Hr Min?

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so FS2004 format is Deg Hr Min?

No. there are no hours! And the format is user selectable, I think -- probably via unpublished options in the CFG file. But you can always tell from the way it is presented. You actually showed them in the Degrees and Minutes format:

I slew to a position of N33* 56.33', W118* 24.29'

See that little sign, ' ? That means "minutes". There's a seconds sign, ". If the format is degrees/minutes/seconds it looks like this:

N33* 56' 33"

When only minutes, no seconds, are given you get the decimal point indicating that the following digits are decimal fractions.

And of course you can also have just degrees with a longer fractional part for similar accuracy.

Pete

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Gotcha Mr D :lol:

What I was doing, as you correctly pointed out, was dividing both parts after the degree ie 33degs then 56/60 and 33/60.

What I should have done is 33degs then divide 56/60 and then .33/60.

Thanks

Gray

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What I should have done is 33degs then divide 56/60 and then .33/60.

Yes, or more simply 33 degrees and 56.33/60. ;-)

Pete

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