Thanks Pete,
Clarifying what I was trying to achieve here:
0=P1,0,K119,10
1=P1,0,K119,10
3=U1,0,K119,10
4=P1,1,K114,10
5=P1,1,K114,10
6=U1,1,K114,10
I wanted an accelerated rate on left turn of the rotary knob, hence:
0=P1,0,K119,10
1=P1,0,K119,10
and I wanted a normal rate on left turn of the rotary knob defining a different single key click Up for this, hence:
3=U1,0,K119,10
Lines 4,5 & 6 for turning the knob to the right in the same fashion (line 2 escaped into the ether somewhere)
The following was an attempt at replicating your manual for using those assignments in a toggle fashion.
7=CP(F+1,5)(+1,1)1,0,C1005,256
8=CU(F+1,5)(+1,1)1,0,C1005,256
9=CP(F-1,5)(+1,1)1,0,C1005,256
10=CU(F-1,5)(+1,1)1,0,C1005,256
I understand in principle what you have explained, but I admit I have to now go away and think on that and read your notes again.
Appreciate your time,
Sincerely, David