Craig Phillips Posted April 2, 2005 Report Share Posted April 2, 2005 Pete I am making a Traffic radar program just like TrafficLook, however my radar screen is "plane is north". If you get what I mean. I have been using the Aviation Formulary at http://williams.best.vwh.net/avform.htm. I can work out the distance and the bearing from the current aircraft to the AI traffic, however I am unable to present it on the Radar screen. I have also been using trigonometry, however I am not familiar with it. I was wondering if you could show me an example of how you present the traffic in TrafficLook. It would be much appriated. Thanks CRaig Link to comment Share on other sites More sharing options...

Pete Dowson Posted April 2, 2005 Report Share Posted April 2, 2005 I can work out the distance and the bearing from the current aircraft to the AI traffic, however I am unable to present it on the Radar screen. I have also been using trigonometry, however I am not familiar with it. If you have distance and bearing (d, b) then you can convert that to some x, y coordinates for a Radar screen. It's simple trig isn't it? Tell me where you are stuck. To keep things easy I tend to do this sort of trig in the four quadrants separately -- saves confusion with signs and so on. For the first quadrant (bearing 0-90, Forward/Right), the (x,y) plot position would be: x = d * cos(b) y = d * sin(b) after converting b to radians of course ( *PI / 180). The other quadrants are variations of this with different sinces and +/-90 sort of fixes. On the other hand, just to map positions relative to the aircraft you don't need distance and bearing. Just use the Lat/Long values, made relative to the user aircraft by subtracting the latter. However, then you'd need to rotate the relative (x,y) coordinates to get bearing up, so you might be better off using distance and bearing in any case. I was wondering if you could show me an example of how you present the traffic in TrafficLook. But TrafficLook merely lists the data, including distance and bearing. it doesn't draw a map. You already have the data that TrafficLook has. Regards, Pete Link to comment Share on other sites More sharing options...

Craig Phillips Posted April 2, 2005 Author Report Share Posted April 2, 2005 I have already used the functions to find out each X and Y, however it does not seem to work.Are the X and Y formulas the same for each quadrant? For example: Bearing > 0 and <90 b=Bearing nm = Distance (nm) x=Cos(b / (180/PI)) * nm y=Sin(b/ (180/PI)) * nm I am stuck on finding the x and y lengths. What are the other X and Y formulas for each quadrant? Thanks Craig Link to comment Share on other sites More sharing options...

Pete Dowson Posted April 2, 2005 Report Share Posted April 2, 2005 I have already used the functions to find out each X and Y, however it does not seem to work.Are the X and Y formulas the same for each quadrant? For example: Bearing > 0 and <90b=Bearing nm = Distance (nm) x=Cos(b / (180/PI)) * nm y=Sin(b/ (180/PI)) * nm I am stuck on finding the x and y lengths. What are the other X and Y formulas for each quadrant? Thanks Craig For 90-180 you can either use the formae exactly as above (sin goes -ve from 90-180), or, for clarity of thought, subtract the bearing from 180 and then do as above, but reversing the sign of y. Draw yourself a little picture. It will all be clear then 180-270 is similar, just subtract 180 and reverse signs on both x and y. 270-360 subtract from 360, reverse the sign of the x value. Regards, Pete Link to comment Share on other sites More sharing options...

Craig Phillips Posted April 2, 2005 Author Report Share Posted April 2, 2005 Yep done all that and it still is not working. Any other suggestions? Link to comment Share on other sites More sharing options...

Pete Dowson Posted April 2, 2005 Report Share Posted April 2, 2005 Yep done all that and it still is not working. Any other suggestions? There's nothing to go wrong if you got the trig correct. What does "not working" mean? I assume you've scaled it to fit your graphics. Don't ask me about graphics, i've no idea about that. Pete Link to comment Share on other sites More sharing options...

Craig Phillips Posted April 3, 2005 Author Report Share Posted April 3, 2005 I did notice a problem that I had with retreiving the traffic data, however that is now resolved. Here is a snipbit of the code, it is in Visual Basic, but it should be easy enough to understand: gcbearing = the bearing from current plane to one of the traffic nmm = is the distance between the two planes in Nautical Miles The Mod function cancels a number down, for example: 369 Mod 360 = 9 180 Mod 90 = 90 181 Mod 90 = 1 (180 / (4 * Atn(1))) = is the radians 127.5 = is the ratio to draw on the radar po = gcbearing Mod 90 po = gcbearing / (180 / (4 * Atn(1))) 'Find the height hi = (Sin(po) * nmm) * 127.3125 'Find the length lo = (Cos(po) * nmm) * 127.3125 'Plot the planes on the radar screen If gcbearing > 0 And gcbearing < 90 Then plane1(i).Top = (plane1(0).Top + hi + (plane1(i).Height / 2)) * 1 plane1(i).Left = (plane1(0).Left + lo + (plane1(i).Width / 2)) * 1 ElseIf gcbearing > 90 And gcbearing < 180 Then plane1(i).Top = (plane1(0).Top + hi + (plane1(i).Height / 2)) * 1 plane1(i).Left = (plane1(0).Left + lo + (plane1(i).Width / 2)) * 1 ElseIf gcbearing > 180 And gcbearing < 270 Then plane1(i).Top = (plane1(0).Top + hi + (plane1(i).Height / 2)) * 1 plane1(i).Left = (plane1(0).Left + lo + (plane1(i).Width / 2)) * 1 ElseIf gcbearing > 270 And gcbearing < 360 Then plane1(i).Top = (plane1(0).Top + hi - (plane1(i).Height / 2)) * 1 plane1(i).Left = (plane1(0).Left + lo - (plane1(i).Width / 2)) * 1 End If I hope this is understandable. Thanks Craig Link to comment Share on other sites More sharing options...

Pete Dowson Posted April 3, 2005 Report Share Posted April 3, 2005 The Mod function cancels a number down, for example: 369 Mod 360 = 9 180 Mod 90 = 90 181 Mod 90 = 1 I'm pretty sure the middle one is wrong. 180 Mod 90 should be 0. This is the same as the % operation in C/C++. (180 / (4 * Atn(1))) = is the radians What an odd way to do it. Don't you have PI defined as a constant? An angle of 45 degrees provides a Tan of 1.0, so the ATAN of 1 will give the radian equivalent of 45 degrees, but it's an odd way. 127.5 = is the ratio to draw on the radar Don't know what that means. And it isn't used below. You use 127.3125 instead? If gcbearing > 0 And gcbearing < 90 ThenElseIf gcbearing > 90 And gcbearing < 180 Then ElseIf gcbearing > 180 And gcbearing < 270 Then ElseIf gcbearing > 270 And gcbearing < 360 Then You exclude exactly 0, 90, 180, 270 from possibility? Sorry, but you need to use a debugger to find out what is wrong. I assume VB comes with a debugger so you can trace through the results? If not, I would strongly advise a change of language. debuggers are essential. Regards, Pete Link to comment Share on other sites More sharing options...

Craig Phillips Posted April 3, 2005 Author Report Share Posted April 3, 2005 Ok thank you for your help anyway. I'll have to try a few more possiblities. And you were correct about 180 mod 90 = 0, sorry about that mistake, also 127.3125 is the number used. Thanks Craig Link to comment Share on other sites More sharing options...

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