Ron Buchwald Posted June 5, 2005 Report Posted June 5, 2005 Hi. I am tring to scale an offset (eleavtor trim) offset 0bc0. the vb pgm works fine, I can read the offset, I now need to scale it down to a value of 0- 255 so I can send this out the serial port to a micro controler. that will then drive a meter 0 to 5 vdc. I see in epicinfo doc. about scaling but do not know how to do this in vb. The value I read is -16383 to 16383. I don't know the math to convert that type number. any help. Ron. vb code snippet if fsuipc_read (&hbc0, 2, varptr (eletrim), dwresult) then if fsuipc_process (dwresult) then pitchtrim.text = (eletrim) end if end
Hockey Posted June 5, 2005 Report Posted June 5, 2005 Hi. I am tring to scale an offset (eleavtor trim) offset 0bc0. the vb pgm works fine, I can read the offset, I now need to scale it down to a value of 0- 255 so I can send this out the serial port to a micro controler. that will then drive a meter 0 to 5 vdc. I see in epicinfo doc. about scaling but do not know how to do this in vb. The value I read is -16383 to 16383. I don't know the math to convert that type number. any help. Ron.vb code snippet if fsuipc_read (&hbc0, 2, varptr (eletrim), dwresult) then if fsuipc_process (dwresult) then pitchtrim.text = (eletrim) end if end What do you mean scale an offset??? First and foremost...I apologize if I cannot answer you, but it's been years since I tinkered with FS stuff....version 5.0 was the last time I flew anything...but I will try and answer or assist your specific question in regards to programming. Anyways, Scale an offset...well you can't...cuz an offset is an offset...you change the number any and you'll change the data your after too... The value returned at offset 0BC0 is an short integer with a range of 32768 or like you said (+-)16383. You cannot do an explicit cast to a BYTE which holds the values 0-255 or (+-)128...cuz you will likely always result in loss of data. So what I would suggest is calculate the percentage of the first and convert that into the byte code your trying to send over the serial port... For instance: a value of 5243... 5243 / 32768 = 0.16 0.16 * 100 = 16% elevator trim Note: The values stored at offset: 0BC0 appears to be signed by the looks of things, so you will need to convert the value into an unsigned value before plugging that into the equation above... Now you calculate the value (If I fail to use proper math terminology...it's cuz...i'm not a math guy...i'm a geek...computers do my work for me :oops: ) required for the serial port based on the percentage above :) So... 16% of 255 (A serial port I believe can send/recv only a single byte at a time which is a 0-255 unsigned) 255 * 0.16 = 40.8 Remember an integer doesn't allow for any precision, so whole numbers are only allowed...so in reality... 40.8 will likely become 40 Not sure what the hell the above process is called...I think it's interpolation or extrapolation or something...but who cares...as long as you understand it and it works :) Hope this helps 8) Cheers :)
Pete Dowson Posted June 5, 2005 Report Posted June 5, 2005 I can read the offset, I now need to scale it down to a value of 0- 255 so I can send this out the serial port to a micro controler. that will then drive a meter 0 to 5 vdc. I see in epicinfo doc. about scaling but do not know how to do this in vb. The value I read is -16383 to 16383. I don't know the math to convert that type number. Convert N from a range of -16384 - +16383 to N2 with a range 0 - 255. N is a 16-bit integer, N2 is a BYTE (8 bit). Use M as an intermediae 32-bit integer 1. Get everything on the same "base" (i.e. starting from 0): M = N (make sure you have enough room -- i.e. 32 bits) M = N + 16384 (now M runs from 0 to 32767) 2. Scale it down from 32767 max to 255 max 00 i.e 32768 different vales to 256 different values: N2 = M * (256 / 32768) or simpler N2 = M / 128 Now this rounds "off". More accurately you should round to "nearest", which would be by: N2 = (M + 64) / 128 You can do this using shifts instead of division: N2 = (M + 64) >> 7 (where >> means "shift right by"). Regards, Pete
Ron Buchwald Posted June 5, 2005 Author Report Posted June 5, 2005 thank you both. you explained to me and it works fine...I knew I could count on you. Ron. thread closed.... :D :D
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